2013
DOI: 10.1090/s0002-9947-2013-05776-5
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Extensions of finite cyclic group actions on non-orientable surfaces

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Cited by 10 publications
(35 citation statements)
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“…, which means that either p = 2 or ( p, q) ∈ {(3, 3), (3,4), (3, 5)}. We fix NEC groups 1 and 2 with signatures (0; +; [2, p, q]; {( )}) and (1; −; [2, p, q]; {−}), denoted respectively by σ 1 and σ 2 .…”
Section: Actions With 3-punctured Disc or Projective Plane As The Quomentioning
confidence: 99%
See 1 more Smart Citation
“…, which means that either p = 2 or ( p, q) ∈ {(3, 3), (3,4), (3, 5)}. We fix NEC groups 1 and 2 with signatures (0; +; [2, p, q]; {( )}) and (1; −; [2, p, q]; {−}), denoted respectively by σ 1 and σ 2 .…”
Section: Actions With 3-punctured Disc or Projective Plane As The Quomentioning
confidence: 99%
“…The case g = 3 is well understood, as the mapping class group of S 3 is isomorphic to GL 2 (Z) (see [8]), and the classification of conjugacy classes of torsion elements in the latter group is known. Another interesting problem concerning cyclic periodic actions on non-orientable surfaces was considered in recent paper [3], where the authors investigated such actions which can not be extended to any bigger group.…”
Section: Introductionmentioning
confidence: 99%
“…Recall from Theorems 2.1 and 2.2 that, in the case of Riemann surfaces, the extendability of a cyclic action depends on the signature and on the surface-kernel epimorphism. In the case of cyclic group actions on non-orientable unbordered surfaces, the situation is surprisingly quite different, as the next theorem, proved in [9], shows.…”
Section: Extendability Of Group Actions On Klein Surfacesmentioning
confidence: 98%
“…where each cone point of order 2 is produced by a fixed point of one of the involutions yz 4t , with 0 ≤ t ≤ 2n − 1; each cone point of order 4 is produced by a fixed point of yz 4l+2 , with 0 ≤ l ≤ 2n − 1; and each point of order δ j is produced by a fixed point of some element in z 2 (i.e., δ j ≥ 2, δ j |4n). By the Riemann-Hurwitz formula we have (12) 2(g − 1) = 16n(γ − 1)…”
Section: 22mentioning
confidence: 99%