ABSTRACT. The smallest number A < oo is found such that for any sequence Y = {Yt, k E Z} with IA'tykl < 1 there exists a u(t), lu(t)l < A, for which the equation y'~(t) = u(t) (-oo < t < oo) has a solution satisfying the conditions 1 [ -h/2-y(k+l)dt, where kEZ, 1show abstract