“…Cases of equality. If min{h 1 (u, A), h 2 (u, A)} = 2/3, then by (4) and the monotonicity properties of h 1 and h 2 , this can only be when A = A 0 (u); on the other hand, the analysis above shows that this can occur only when A = 0, so we must have A = A 0 (u) = 0 and thus u = 1. Furthermore, to have the equality min{|f (1)|, |f (ue iθ )|/u} = 2/3, we must have, for all t ∈ (0, 1), equality in at least one of the estimates which are equal and are < 2/3 unless e iθ = −1, so that the critical points of f are then ±1.…”