1999
DOI: 10.1016/s0958-9465(99)00004-9
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Fatigue life analysis of fiber reinforced concrete with a fracture mechanics based model

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Cited by 57 publications
(26 citation statements)
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“…This 6 is a study that further developed the previous studies by Li and Matsumoto [20]and Matsumoto and Li [21]. The study employed finite element method to analyze the fatigue behavior of SHFRCC, and successfully reproduced fatigue crack propagation and subsequent fracture.…”
Section: Introductionmentioning
confidence: 78%
“…This 6 is a study that further developed the previous studies by Li and Matsumoto [20]and Matsumoto and Li [21]. The study employed finite element method to analyze the fatigue behavior of SHFRCC, and successfully reproduced fatigue crack propagation and subsequent fracture.…”
Section: Introductionmentioning
confidence: 78%
“…For the sake of comparison, the predictions of the present model in terms of unstable fracture bending moment are reported in Table 1 together with those of the theoretical model by Matsumoto and Li (1999), for different values of the crack depth. Note that the reported results of Matsumoto and Li refer to the net contribution of fibers to crack bridging, i.e.…”
Section: Illustrative Numerical Examplesmentioning
confidence: 99%
“…Some theoretical models have been proposed to describe such phenomena and predict fatigue life (e.g. for metal-matrix composites with continuous fibers, see the models reported in Bao andBegley and for cementitious composites with short fibers, see the recent models presented in Zhang and Stang, 1998, Zhang et al, 1999, and Matsumoto and Li, 1999. In the present paper, a cracked portion of a straight beam subjected to an external cyclic bending moment and the crack bridging actions due to the fibers is analysed (Fig.…”
Section: Introductionmentioning
confidence: 95%
“…Here, in addition to the law under monotonic loading, the law under cyclic loading is required. These two equations (8) and (9) The first tam for fibers that have been in debonding stage can be obtained with the use of (8). Replacing z/(Lf/2) with z', the integration leads to where z0=1-•@ , ƒ¢ƒÂ=ƒ¢ƒÂ/(Lf/2), and ƒÂmax= ƒÂmax /(Lf/2).…”
Section: Introductionmentioning
confidence: 99%