“…By qualitative analysis we could find no titanium in the compound, suggesting that a transfer of the cyclopentadienyl group from titanium to the indium atom had taken place together with a formal proton abstraction from C 5 H 5 – (considering the integrals in the 1 H NMR spectrum). Transformations of C 5 H 5 (E) (E = mono‐valent metal centered substituent) into C 5 H 4 (E) 2 , C 5 H 4 (E)(E′) or C 5 H 4 (E′)(E′) (E′ = main group metal centered substituent) have been investigated in view of the synthesis of ansa –metallocenes and can be performed with lithium organyls or even metal‐alkoxides followed by salt eliminations:, an instructive example is the formation of C 5 H 4 (SiMe 2 ‐SiMe 2 ) 2 C 5 H 4 , which has some resemblance to 2 (see below) . Interestingly the bridging C 5 H 4 groups in this exemplary compound may connect in 1,1‐, 1,2‐ and 1,3‐positions of the ring due to 1,5‐sigmatropic shifts of the silyl groups, whereas only the 1,1‐bridge is active in 2 .…”