2000
DOI: 10.1006/jabr.2000.8371
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Finite Simple Groups of Bounded Subgroup Chain Length

Abstract: Journal of Algebra 231 (2000) 374-386. doi:10.1006/jabr.2000.8371Received by publisher: 1999-11-15Harvest Date: 2016-01-04 12:19:58DOI: 10.1006/jabr.2000.8371Page Range: 374-38

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Cited by 9 publications
(25 citation statements)
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“…Example 2.13. By [1,Corollary 4.2], there are infinitely primes p such that Ω(p 2 −1) ≤ 21. For every such prime p, the exponent of PSL 2 (p) divides N p := p(p 2 − 1), so the word map (x, y) → x Np y Np cannot be surjective on PSL 2 (p) (its image consists only of the identity element); on the other hand, π(N p ) ≤ Ω(N p ) ≤ 22.…”
Section: Preliminariesmentioning
confidence: 99%
“…Example 2.13. By [1,Corollary 4.2], there are infinitely primes p such that Ω(p 2 −1) ≤ 21. For every such prime p, the exponent of PSL 2 (p) divides N p := p(p 2 − 1), so the word map (x, y) → x Np y Np cannot be surjective on PSL 2 (p) (its image consists only of the identity element); on the other hand, π(N p ) ≤ Ω(N p ) ≤ 22.…”
Section: Preliminariesmentioning
confidence: 99%
“…And are there infinitely many primes q such that l(PSL(2, q)) = 5 and 7 ≤ Ω(|PSL(2, q)|) ≤ 8? Through intense numbertheoretic analysis, Alladi et al [1] were able to prove that there exist infinitely many primes q such that l(PSL(2, q)) ≤ 20, but this result does not necessarily provide a positive answer to either question. In fact, the problem is deeper than one might suspect.…”
Section: Final Remarksmentioning
confidence: 99%
“…Notice that the previous theorem cannot be deduced from Theorem 1. For example ρ(PSL(2, p)) = 2 for every prime p and it follows from [1,Corollary 4.2] that there are infinitely many primes p such that | PSL(2, p)| is divisible by at most 20 primes.…”
Section: Introductionmentioning
confidence: 99%