“…Proof. Since τ and T are compatible, the spaces (E, τ ) and (E, T ) have the same (p, q)-limited subsets by Lemma 3.1(vii) of [24]. As by assumption all (p, q)-limited sets in (E, T ) are precompact (resp., sequentially precompact, relatively compact or relatively sequentially compact), the inclusion τ ⊆ T implies that so are all (p, q)-limited sets also in (E, τ ).…”