Proceedings of 14th VLSI Test Symposium
DOI: 10.1109/vtest.1996.510854
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Full fault dictionary storage based on labeled tree encoding

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Cited by 60 publications
(32 citation statements)
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“…As an example consider the tree of 11 nodes, labeled from 0 to 10 in Fig.1a in which the path 1 0 is (1,4,6,8,3,0). We obtain f 0 = 1,…”
Section: The Dandelion Codementioning
confidence: 99%
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“…As an example consider the tree of 11 nodes, labeled from 0 to 10 in Fig.1a in which the path 1 0 is (1,4,6,8,3,0). We obtain f 0 = 1,…”
Section: The Dandelion Codementioning
confidence: 99%
“…In our example, since f 0 = 1, f 1 = 8, and f 2 = 3, the algorithm set g [3] ← g [8] = 3, introducing a loop, and g [8] ← g [1] = 4, introducing a cycle. Fig.1d shows the resulting digraph: the associated codeword is W = [6,3,6,1,8,8,4,1,9].…”
Section: The Dandelion Codementioning
confidence: 99%
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