2022
DOI: 10.1080/03081087.2022.2111544
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Further results on strongly core orthogonal matrix

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Cited by 3 publications
(2 citation statements)
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“…In [3], we can see that A ⊥ s, # ⃝ B implies (A + B) # ⃝ = A # ⃝ + B # ⃝ (core additivity). In [4], Liu, Wang, and Wang proved that A, B ∈ C n×n with Ind(A) ≤ 1 and Ind(B) ≤ 1 are strongly core orthogonal, if and only if (A + B) # ⃝ = A # ⃝ + B # ⃝ and A # ⃝ B = 0 (or BA # ⃝ = 0), instead of A ⊥ # ⃝ B, which is more concise than Theorem 7.3 in [3]. And, Ferreyra and Malik in [3], have proven that if A is strongly core orthogonal to B, then rk(A + B) =rk(A)+rk(B) and (A + B) # ⃝ = A # ⃝ + B # ⃝ .…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…In [3], we can see that A ⊥ s, # ⃝ B implies (A + B) # ⃝ = A # ⃝ + B # ⃝ (core additivity). In [4], Liu, Wang, and Wang proved that A, B ∈ C n×n with Ind(A) ≤ 1 and Ind(B) ≤ 1 are strongly core orthogonal, if and only if (A + B) # ⃝ = A # ⃝ + B # ⃝ and A # ⃝ B = 0 (or BA # ⃝ = 0), instead of A ⊥ # ⃝ B, which is more concise than Theorem 7.3 in [3]. And, Ferreyra and Malik in [3], have proven that if A is strongly core orthogonal to B, then rk(A + B) =rk(A)+rk(B) and (A + B) # ⃝ = A # ⃝ + B # ⃝ .…”
Section: Introductionmentioning
confidence: 99%
“…But, whether the reverse holds is still an open question. In [4], Liu, Wang, and Wang solved the problem completely. Furthermore, they also gave some new equivalent conditions for the strongly core orthogonality, which are related to the minus partial order and some Hermitian matrices.…”
Section: Introductionmentioning
confidence: 99%