1988
DOI: 10.1016/0022-4049(88)90080-1
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G-domains and spectral spaces

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Cited by 4 publications
(1 citation statement)
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“…Proof. Since D and D are semi normal [11], and I = I [10], On the other hand, if ∃P ∈ Spec(D) such that P / ∈ S(D), then D P is a discrete valuation ring [15]. But then,D P being a valuation domain, P D P = P implies that D P = (P : P ) and hence (P : P ) is a rank one valuation ring.…”
Section: Theorem 16mentioning
confidence: 99%
“…Proof. Since D and D are semi normal [11], and I = I [10], On the other hand, if ∃P ∈ Spec(D) such that P / ∈ S(D), then D P is a discrete valuation ring [15]. But then,D P being a valuation domain, P D P = P implies that D P = (P : P ) and hence (P : P ) is a rank one valuation ring.…”
Section: Theorem 16mentioning
confidence: 99%