2005
DOI: 10.1007/bf02786686
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Galois embedding problems with cyclic quotient of orderp

Abstract: Let K/F be a cyclic field extension of odd prime degree. We consider Galois embedding problems involving Galois groups with common quotient Gal(K/F ) such that corresponding normal subgroups are indecomposable F p [Gal(K/F )]-modules. For these embedding problems we prove conditions on solvability, formulas for explicit construction, and results on automatic realizability.

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Cited by 20 publications
(22 citation statements)
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“…We take this approach in proving Theorem 1.1, which establishes automatic realizations for a useful family of finite metacyclic p-groups. Our methods extend those of [10], [11] and [12]. It is interesting to observe that, although not visible here, the essential fact underpinning our results is Hilbert 90.…”
Section: Introductionsupporting
confidence: 60%
“…We take this approach in proving Theorem 1.1, which establishes automatic realizations for a useful family of finite metacyclic p-groups. Our methods extend those of [10], [11] and [12]. It is interesting to observe that, although not visible here, the essential fact underpinning our results is Hilbert 90.…”
Section: Introductionsupporting
confidence: 60%
“…We argue by induction on N with N = 0 being trivial. By induction D = P N ⊕ Q N , where P N is as in (14), and Q N has no summands of dimension ≤ N . The induction hypothesis applied to Q N also shows that U n−1 (Q N ) = 0 for all n ≤ N , as otherwise Q N would have direct Z-summands of dimension 1 ≤ d ≤ N .…”
Section: Ulm Invariants and Finite Summandsmentioning
confidence: 99%
“…The proof splits into finding the multiplicity of the infinite and finite indecomposable direct Z-summands. In contrast to the work of Mináč, Schultz and Swallow [14,13], this approach also allows dealing with modules over an infinite group such as Z, cf. Section 5.1…”
Section: Introductionmentioning
confidence: 95%
“…On the other hand Gal(K /K) has exponent p 2 so if K ⊂ LK m then also Gal(LK m /K) does, having Gal(K m /K) exponent p we would have a contradiction if Gal(L/K) had exponent p too. If Gal(L/F ) has greatest possible length m = p, then there is only one possibility for the isomorphism class, which is the wreath product of two cyclic groups of order p, see [MS05,Wat94].…”
Section: 2mentioning
confidence: 99%
“…Gal(L/F ) is a cyclic and indecomposable Gal(F/K)-module of length ≤ p, and the isomorphism class of the group Gal(L/F ) is identified by the length of Gal(L/F ) as Gal(F/K)-module, and by its exponent (see [MS05,Wat94]). …”
Section: Introductionmentioning
confidence: 99%