2009
DOI: 10.1016/j.physletb.2009.03.065
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Gauging U(1) symmetries and the number of right-handed neutrinos

Abstract: In this letter we consider that assuming: a) that the only left-handed neutral fermions are the active neutrinos, b) that B − L is a gauge symmetry, and c) that the L assignment is restricted to the integer numbers, the anomaly cancellation imply that at least three right-handed neutrinos must be added to the minimal representation content of the electroweak standard model. However, two types of models arise: i) the usual one where each of the three identical right-handed neutrinos has total lepton number L = … Show more

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Cited by 114 publications
(105 citation statements)
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“…[20,21]. It is an extension of the SM based on the gauge symmetry SUð2Þ L ⊗ Uð1Þ Y 0 ⊗ Uð1Þ B−L , where B and L are the usual baryonic and leptonic numbers, respectively, and Y 0 is a new charge different from the hypercharge Y of the SM.…”
Section: Brief Review Of the B − L Modelmentioning
confidence: 99%
See 2 more Smart Citations
“…[20,21]. It is an extension of the SM based on the gauge symmetry SUð2Þ L ⊗ Uð1Þ Y 0 ⊗ Uð1Þ B−L , where B and L are the usual baryonic and leptonic numbers, respectively, and Y 0 is a new charge different from the hypercharge Y of the SM.…”
Section: Brief Review Of the B − L Modelmentioning
confidence: 99%
“…The values of Y 0 are chosen to obtain the hypercharge Y through the relation Y ¼ ½Y 0 þ ðB − LÞ , after the first spontaneous symmetry breaking. Assuming a generationindependent charge assignment and the nonexistence of mirror fermions, and by restricting ourselves to integer quantum numbers for the Y 0 charge, the anomaly cancellation constrains the number of right-handed neutrinos, n R ≥ 3 [20]. Considering n R ¼ 3, there is an exotic charge assignment for the Y 0 charge where Y 0 n R1 ;n R2 ¼ −4 and Y 0 n R3 ¼ 5 besides the usual one where Y 0 n Ri ¼ 1 with i ¼ 1; 2; 3.…”
Section: Brief Review Of the B − L Modelmentioning
confidence: 99%
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“…Assuming three generations, two active and one sterile right-handed neutrinos, the anomaly-free system of equations implies the charge assignments given in the last column of Table I. For ¼ 6, the hypercharge is reproduced, while ¼ 3 does not lead to B À L since x ';e ¼ À1, x u;d;q ¼ 1=3, x ¼ À4, and x S ¼ 5 [10].…”
Section: B Type-iii Seesaw Case With N T ¼ N Gmentioning
confidence: 99%
“…Some models which have an extra U (1) gauge group [13,14] also deserve a detailed study in order to predict new physics behavior. The cumulative study of different models, candidates to describe the electroweak interaction, can guide the LHC data analysis if in fact a Z ′ is discovered.…”
Section: Introductionmentioning
confidence: 99%