“…Therefore, the coefficient of a second order univariate Taylor expansion cannot directly be used to compute the mixed derivative (23b). In particular, if we simply set s 1 = s 2 = t and x(t) = w(t, t), we obtain the Taylor coefficient (24) of (17) with x 1 = w 1 + w 2 and x 2 = w 11 + w 12 + w 22 , which is not the desired derivative (23b). In theory, derivative (23b) could be calculated from linear combinations of the vector y 2 for a set of appropriate Taylor coefficients of (22) as suggested in [10,12].…”