2003
DOI: 10.1007/978-3-540-45138-9_30
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Generalized Satisfiability with Limited Occurrences per Variable: A Study through Delta-Matroid Parity

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Cited by 29 publications
(42 citation statements)
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“…By now there is strong supporting evidence for the conjecture -in the intervening years it has been verified in many cases [11,12,13,23,24,14,38,40,51,53,54,55,60,61,62,63,67,72,136,140,171], cf. [52,106], prominently including CSP(H) for structures H with up to three vertices [25], extending the Boolean Dichotomy of [179], and for conservative structures [23], discussed in Section 5.…”
Section: H Has a Loopmentioning
confidence: 96%
“…By now there is strong supporting evidence for the conjecture -in the intervening years it has been verified in many cases [11,12,13,23,24,14,38,40,51,53,54,55,60,61,62,63,67,72,136,140,171], cf. [52,106], prominently including CSP(H) for structures H with up to three vertices [25], extending the Boolean Dichotomy of [179], and for conservative structures [23], discussed in Section 5.…”
Section: H Has a Loopmentioning
confidence: 96%
“…A key technique in proving hardness results for #CSP and related problems is pinning [12,14,19,20,23,25]. We write R zero = {0} and R one = {1} for the two unary relations that contain only zero and one, respectively.…”
Section: Boolean Constraint Satisfaction Problemsmentioning
confidence: 99%
“…Restricting the degree of instances (the maximum number of times that each variable may appear in the scopes of constraints) is incomparable but not much is known in this case. In the non-uniform Boolean case, Dalmau and Ford have shown that, as long as Γ contains the relations R zero = {0} and R one = {1}, CSP(Γ ) for instances of degree at most three has the same complexity as the case with no degree restrictions [14]. The degree-2 case has not yet been completely classified, though it is known that degree-2 CSP(Γ ) is as hard as general CSP(Γ ) whenever Γ contains R zero and R one and some relation that is not a -matroid [14,25].…”
mentioning
confidence: 97%
“…If we start with a SAT instance with the number of occurrences per variable bounded by three (also an NP-complete problem [2]), we end with (V , F ) planar (each component of (V , F ) contains at most three vertices). Thus, the PAFP is NP-complete even if both G = (V , E) and (V , F ) are planar.…”
Section: Preliminariesmentioning
confidence: 99%