2020
DOI: 10.1093/imrn/rnaa027
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Genus One Cobordisms Between Torus Knots

Abstract: We determine the pairs of torus knots that have a genus one cobordism between them, with one notable exception. This is done by combining obstructions using ν + from the Heegaard Floer knot complex and explicit cobordisms constructions. As an application, we determine the induced subgraph of the Gordian graph on the set of vertices that are given by torus knots. Also, we determine the pairs of Thurston-Bennequin number maximizing Legendrian torus knots that have a genus one exact Lagrangian cobordism, with one… Show more

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Cited by 4 publications
(4 citation statements)
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“…Firstly, when determining Gordian distance 1 pairs of torus knots, we relied on ν + , but speculated that the proof could be done using the Tristram-Levine signatures [Tri69,Lev69]; see [FP19,Remark 4•3]. Here, we partially confirm this speculation using signature calculations via the Hirzebruch-Brieskorn formula [Bri66,GG05].…”
Section: Introductionmentioning
confidence: 62%
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“…Firstly, when determining Gordian distance 1 pairs of torus knots, we relied on ν + , but speculated that the proof could be done using the Tristram-Levine signatures [Tri69,Lev69]; see [FP19,Remark 4•3]. Here, we partially confirm this speculation using signature calculations via the Hirzebruch-Brieskorn formula [Bri66,GG05].…”
Section: Introductionmentioning
confidence: 62%
“…This was done by comparing explicit constructions of cobordisms with the lower bound for the cobordism distance using the ν + -invariant [HW16] from the Heegaard Floer knot complex. As an application, the authors determined which pairs of torus knots have Gordian distance 1; see [FP19,Corollary 1.3]. The first result of this paper has two motivations.…”
Section: Introductionmentioning
confidence: 95%
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“…For instance, for distinct positive parameters, Litherland [15] proved that the torus knots T (p, q) and T (p , q ) are linearly independent. On the other hand, Feller-Park [6] analyzed the question of determining for which pairs d(T (p, q), T (p , q )) = 1, resolving all but one case: d(T (3, 14), T (5, 8)). Related work includes [1,5] The triangle inequality states that for all K and J, d(K, J) ≤ g 4 (K) + g 4 (J).…”
Section: Introductionmentioning
confidence: 99%