2010
DOI: 10.1134/s003602441012006x
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Gibbs energies of formation of hydroxides of lanthanides and yttrium

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Cited by 18 publications
(14 citation statements)
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“…Saturation of solutions is impossible, when solubility product (SP) for sulfide La (10 -26.3 by [9]) keeps minimum and its activities product (AP) (on the average is 10 -34 ) keeps maximum. Therefore, the absence of a pronounced positive Ce anomaly in the waters with reducing conditions (with 3 + oxidation state) can be explained by the formation of poorly soluble hydroxide Се(ОН)3 (SP = 6.4310 -26.4 by [10]). In the oxidizing conditions stability of cerium in the waters can be controlled by hydroxide Ce(OH)4; its formation is possible for all lakes (AP is 10 -41 and SP is 1.610 -55 the same link).…”
Section: Resultsmentioning
confidence: 99%
“…Saturation of solutions is impossible, when solubility product (SP) for sulfide La (10 -26.3 by [9]) keeps minimum and its activities product (AP) (on the average is 10 -34 ) keeps maximum. Therefore, the absence of a pronounced positive Ce anomaly in the waters with reducing conditions (with 3 + oxidation state) can be explained by the formation of poorly soluble hydroxide Се(ОН)3 (SP = 6.4310 -26.4 by [10]). In the oxidizing conditions stability of cerium in the waters can be controlled by hydroxide Ce(OH)4; its formation is possible for all lakes (AP is 10 -41 and SP is 1.610 -55 the same link).…”
Section: Resultsmentioning
confidence: 99%
“…Yttrium recovery in the absence of chloride ions at maximum recovery рН of 6.9 occurs in a form of YOH(DS) 2 , and at chloride concentrations of 0.01 M in a form of Y(OH) 3 6.6 [Chirkst et al 2009c]. In the range of maximum recovery The influence of chloride ions on the distribution coefficient was explained by comparing chloro and hydroxo complexes instability constants ( Table 2).…”
Section: Resultsmentioning
confidence: 99%
“…The solubility of Eu(OH) 3 (s) has been investigated in several literatures [4,15,16,18,24,25,[39][40][41][42]. Akselrud and Ermolenko [18] observed starting points of precipitation by adding NaOH solutions to Eu solution in certain concentrations.…”
Section: Eu Solubilities Measured At 25 °C After Aging At 25 Tomentioning
confidence: 99%
“…The solubility products at T meas = 25 °C were determined to be log K s° = 18.4±0.2 for Eu 2 O 3 (cr), and log K s° = 17.2±0.3 for Eu(OH) 3 (cr). In literatures, a number of log K s° for Eu(OH) 3 (cr) has been reported [15,16,18,25,[39][40][41][42], while no log K s° value for Eu 2 O 3 (cr). The obtained log K s° for Eu(OH) 3 (cr) in the present study was slightly higher than the reported values and the selected one of log K s° = 16.48±0.30 in [4].…”
Section: Solubility Product Of Ln 2 O 3 (Cr) and Ln(oh) 3 (Cr) At T Mmentioning
confidence: 99%