“…It remains to consider 2 < q < ∞, for which we setα 0 = qα/2, o 1 = o(q − 2)/(q − o), s 1 = qs/(q −2). Similarly to the proof in subsection 3.1, we have α 0 ≤ 1/2, 2 ≤ o 1 ≤ ∞ and 1/2 − 1/o 1 ≤ s 1 < n/2, by the conditions on q, o, α and s. Moreover, for θ = 1 − 2/q ∈ (0, 1)θ)0 + θs 1 = s.Firstly when q = o and s = 1/2 − 1/o, where o 1 = ∞ and s 1 = 1/2 − 1/o 1 , by(11) and(12) we obtain…”