“…Then either M ∂ a y (t, a) = 0 or M ∂ a y (t, a) = 0.In the first case,(15) implies that M ∂ a y (t, a) and (Y (a) − M y (t, a)) are collinear, and so are M ∂ aȳ (t, a) and (Ȳ (a) − Mȳ(t, a)). It follows that (Y (a) −Ȳ (a)) and M ∂ a y (t, a) are collinear, which yields(20). Moreover, Y (a) − M y (t, a) andȲ (a) − Mȳ(t, a) are also collinear and consequently(21) holds.In the second case, (16) yields βI(t − a)( X(a) − y(t, a)) = 0.…”