“…(iv) ⇒ (v): Assume (iv). By[32, Lemma D], it suffices to prove that if Q ∈ Spec(R ), with n := ht R (Q) (< ∞), and q := Q ∩ R (∈ Max(R)), with m := ht R (q) (< ∞), then n = m. In view of the conditions in (iv), we can assume, without loss of generality, that Q is a non-maximal prime ideal of R and that q is unibranched in R . As the assertion is trivial if Q (or q) is (0), we can also assume that n = 0 and m = 0.…”