2011
DOI: 10.1016/j.jalgebra.2010.10.032
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Gröbner bases of syzygies and Stanley depth

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Cited by 5 publications
(5 citation statements)
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“…It is easy to see that the corollary holds for n ≤ 2. If n ≥ 3 then sdepth S I ≥ 2 = depth I by [3,Theorem 3.4], which is enough as shows our Lemma 1.3. For the sake of the completeness we give below another proof applying the above proposition.…”
Section: Big Size Onementioning
confidence: 68%
“…It is easy to see that the corollary holds for n ≤ 2. If n ≥ 3 then sdepth S I ≥ 2 = depth I by [3,Theorem 3.4], which is enough as shows our Lemma 1.3. For the sake of the completeness we give below another proof applying the above proposition.…”
Section: Big Size Onementioning
confidence: 68%
“…However since m i KOEZ i is a free KOEZ i -submodule of M and since x j m D 0 for all j , this is only possible if KOEZ i D K. Thus sdepth.M / D 0.As a second application we obtain the following result of[62, Theorem 2.2], see also[31, Corollary 2.12].Theorem 28. This yields the desired conclusion.…”
mentioning
confidence: 74%
“…In Sect. The first is that Stanley depth zero implies depth zero, the second is that the kth syzygy module of a Z n -graded module has Stanley depth at least k. The second result (with a more difficult argument) was first shown in [62]. This result has two nice consequences which we cite from [32].…”
Section: Introductionmentioning
confidence: 86%
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