2013
DOI: 10.1073/pnas.1218426110
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Groups of piecewise projective homeomorphisms

Abstract: The group of piecewise projective homeomorphisms of the line provides straightforward torsion-free counterexamples to the socalled von Neumann conjecture. The examples are so simple that many additional properties can be established.free groups | paradoxical decomposition | von Neumann problem

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Cited by 89 publications
(82 citation statements)
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“…In this section we show that this is not the only obstruction. We consider a group H of piecewise projective orientation-preserving homeomorphisms of R intruduced in [Mon13]. A self-homeomorphisms f of R belongs to this group if there exist intervals I 1 , .…”
Section: Connection With Topological Full Groups and Liouville Propermentioning
confidence: 99%
See 1 more Smart Citation
“…In this section we show that this is not the only obstruction. We consider a group H of piecewise projective orientation-preserving homeomorphisms of R intruduced in [Mon13]. A self-homeomorphisms f of R belongs to this group if there exist intervals I 1 , .…”
Section: Connection With Topological Full Groups and Liouville Propermentioning
confidence: 99%
“…The fact that H R is not extensively amenable follows from the following Theorem because it was proved in [Mon13] that H is not amenable. The proof relies on the main result in [JNdlS13].…”
Section: Connection With Topological Full Groups and Liouville Propermentioning
confidence: 99%
“…The following theorem of Monod is remarkable both for its strength and for the simplicity of the proof 302 Theorem 5.9.21 (Monod,[234]). For every ring A ≤ R containing 1, A ≠ Z, the group H(A) is non-amenable and contains no free non-cyclic subgroups.…”
Section: Two Church-rosser Presentations Of Fmentioning
confidence: 99%
“…Monod constructs in [34] a class of groups of piecewise projective homeomorphisms HpAq (where A is a subring of R). By comparing the action of HpAq on the projective line P 1 pRq with that of P SL 2 pAq, he proves that it is non-amenable for A ‰ Z and without free subgroups for all A.…”
Section: Introductionmentioning
confidence: 99%