1997
DOI: 10.1090/s0002-9939-97-03752-0
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Growth of graded noetherian rings

Abstract: Abstract. We show that every graded locally finite right noetherian algebra has sub-exponential growth. As a consequence, every noetherian algebra with exponential growth has no finite dimensional filtration which leads to a right (or left) noetherian associated graded algebra. We also prove that every connected graded right noetherian algebra with finite global dimension has finite GK-dimension. Using this, we can classify all connected graded noetherian algebras of global dimension two. IntroductionThe study… Show more

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Cited by 95 publications
(45 citation statements)
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“…for m ≫ 0. Thus the associated twisted homogenous coordinate ring has exponential growth and hence is not (right or left) noetherian [SZ,Theorem 0.1]. So D cannot be right σ −1 -ample, by [AV,Theorem 1.4].…”
Section: Now a Graded Ringmentioning
confidence: 99%
“…for m ≫ 0. Thus the associated twisted homogenous coordinate ring has exponential growth and hence is not (right or left) noetherian [SZ,Theorem 0.1]. So D cannot be right σ −1 -ample, by [AV,Theorem 1.4].…”
Section: Now a Graded Ringmentioning
confidence: 99%
“…(a) and (b) are proved in [SteZ,3.1.1]. Part (c) is given in the proof of [SteZ,3.1.4]. We repeat the main idea here.…”
Section: Artin-schelter Regular Algebrasmentioning
confidence: 86%
“…By the claim proved in the last paragraph one sees that GKdim A > 2. Finally, the GK-dimension of a noetherian AS regular algebra is an integer [SteZ,2.4], so GKdim ≥ 3. Now we start to focus on AS regular algebras of global dimension 4.…”
Section: Lemma 12 If a Is A Noetherian As Regular Algebra Of Global D...mentioning
confidence: 99%
See 1 more Smart Citation
“…• ϕ(g), for any x ∈ S and g ∈ F r . If we insist that the growth functions should be equivalent under semi-isomorphisms then, as we see, for instance, in [18], all functions with exponential growth fall into the same equivalence class. Using recent results in [8] and [9], we give in Subsection 6.2 examples where S and S are semi-isomorphic, the growth of S is maximal and the growth of S is not.…”
Section: Introductionmentioning
confidence: 92%