An exact diagonalization method is used to calculate corrections to the ground state of the 4He atom related to the finite size and finite mass of its nucleus, which is interpreted as a bound state of two deuterons in the shell model. The experimentally determined quadrupole moment of the deuteron (Q0 = 2.74 × 10−27 cm2) makes it possible to estimate the size of an individual deuteron and, thereby, the size of the 4He nucleus (d ∼ 1.5 × 10−13 cm). As a result, the 4He nucleus is made up of four nucleons in the ground state (1s)4 in a spherically symmetric shell of diameter d, along which the complete charge (+2e) of the nucleus is uniformly distributed. This distribution, in turn, can be interpreted as the ground state of a rigid rotator with charges of magnitude +e attached to its ends. In this model the nucleus is a charged spherical shell of radius d/2, within which the potential is constant and finite, equal to 4e/d, and outside of which the potential falls off in accordance with the conventional Coulomb law as 2e/r. The existence of a “core” of this kind signifies a correction to the standard Coulomb potential for r < d/2 that reduces the energy of the ground state of the 4He atom by a small amount ε1 but does not lead to any new low-energy levels. This reduction, in turn, is comparable to the correction to the ground state of 4He owing to the finite mass of the nucleus.