2018
DOI: 10.1088/1751-8121/aab215
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Hidden supersymmetry and quadratic deformations of the space-time conformal superalgebra

Abstract: We analyze the structure of the family of quadratic superalgebras, introduced in J Phys A 44(23):235205 (2011), for the quadratic deformations of N = 1 space-time conformal supersymmetry. We characterize in particular the 'zero-step' modules for this case. In such modules, the odd generators vanish identically, and the quadratic superalgebra is realized on a single irreducible representation of the even subalgebra (which is a Lie algebra). In the case under study, the quadratic deformations of N = 1 space-time… Show more

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Cited by 14 publications
(18 citation statements)
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References 42 publications
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“…The sub-structures discovered will allow further application of algebraic method for higher rank polynomial algebras and corresponding superintegrable models. Quadratic deformation of Lie super algebras have been observed in other context [21].…”
Section: Discussionmentioning
confidence: 93%
“…The sub-structures discovered will allow further application of algebraic method for higher rank polynomial algebras and corresponding superintegrable models. Quadratic deformation of Lie super algebras have been observed in other context [21].…”
Section: Discussionmentioning
confidence: 93%
“…Another possible direction of further investigation is to consider our construction embedded in the Lie superalgebra of SU(2,2/1) which is isomorphic to the algebra of the superconformal spacetime symmetry group [88]. Gauging of the latter leads to N = 1 conformal supergravity [8,7,89,90,91].…”
Section: Discussionmentioning
confidence: 99%
“…It follows at once from these commutators that the polynomials {M 1 , M 3 − M 4 , M 5 } do no more generate a quadratic algebra, but a solvable Lie algebra isomorphic to b ⊕ R. 4 3 The Conformal Galilean algebra S(3)…”
Section: Extended Cartan Solvablementioning
confidence: 99%
“…Now [Z 1 , A 6 ] shows that the polynomial Z 2 = P 2 2 P 2 1 H must also be added to the generators if the algebra is to be quadratic. On the other hand, the commutator [Z 1 , Z 2 ] implies that Z 3 = P 4 2 P 1 P 0 H must also belong to the set of generators. Evaluating recursively the commutators of Z 1 and A 6 with Z k for k ≥ 2, we find that the monomials of the type P α+3β 2 P α 1 P β 0 H with α, β ∈ N must be taken as generators, hence leading to a quadratic algebra that is not finitely generated.…”
Section: Cartan Casementioning
confidence: 99%
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