“…Hence, θ 0 (X) ∈ Im H has a non-zero projection to Rj ⊂ Im H. Since R(I s q, X) = (0, 0, 0, θ s (X)) ∈ g, there exists α, β ∈ R such that α = 0 and (0, 0, 0, αj + βk) ∈ g. We may assume that α 2 + β 2 = 1. In [8,Lemma 6] it is shown that there exists x, y ∈ R such that x 2 + y 2 = 1 and with respect to the new basis with p ′ = (x + iy)p and q ′ = (x + iy)q the elements (0, 0, 0, i) ∈ g and (0, 0, 0, αj + βk) ∈ g have the form (0, 0, 0, i) and (0, 0, 0, j), respectively. Note that S 03 = −iS 02 = 0.…”