2015
DOI: 10.1016/j.jalgebra.2015.05.032
|View full text |Cite
|
Sign up to set email alerts
|

Hom-L-R-smash products, Hom-diagonal crossed products and the Drinfeld double of a Hom-Hopf algebra

Abstract: We introduce the Hom-analogue of the L-R-smash product and use it to define the Homanalogue of the diagonal crossed product. When H is a finite dimensional Hom-Hopf algebra with bijective antipode and bijective structure map, we define the Drinfeld double of H; its algebra structure is a Hom-diagonal crossed product and it has all expected properties, namely it is quasitriangular and modules over it coincide with left-right Yetter-Drinfeld modules over H.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
2
1

Citation Types

0
22
0

Year Published

2016
2016
2023
2023

Publication Types

Select...
8

Relationship

0
8

Authors

Journals

citations
Cited by 35 publications
(22 citation statements)
references
References 41 publications
0
22
0
Order By: Relevance
“…In this section, we will recall the definitions in [8] on the Hom-Hopf algebras, Hommodules and Hom-comodules.…”
Section: Preliminariesmentioning
confidence: 99%
See 2 more Smart Citations
“…In this section, we will recall the definitions in [8] on the Hom-Hopf algebras, Hommodules and Hom-comodules.…”
Section: Preliminariesmentioning
confidence: 99%
“…for any a ∈ A and h ∈ H. By Proposition 2.6 in [8], in order to prove the multiplication is Hom-associative, we need only to verify that T is a Hom-twisting map between H and A. Indeed, first easy to see that…”
Section: That Is (H α) Is a Left (H Op α)-Module Hom-algebramentioning
confidence: 99%
See 1 more Smart Citation
“…In this section, we will recall the definitions in [20] on Hom-Hopf algebras, Hom-modules and Homcomodules.…”
Section: Preliminarymentioning
confidence: 99%
“…Recall from [17] that let (A, β A ) and (B, β B ) be two Hom-associative algebras and a linear map R : A ⊗ B → B ⊗ A with R(b ⊗ a) = a R ⊗ b R = a r ⊗ b r satisfying the conditions:…”
Section: Using This Equality One Can Computesmentioning
confidence: 99%