“…For H diffusion in HfCr 2 H 0.4 , we may safely assume that f = 1, since only less than 4% of all available tetrahedral sites are occupied by hydrogen. Using the proton spin-lattice relaxation data for HfCr 2 H 0.3 [15] and the Bloembergen-Purcell-Pound model [6], we estimate that d ≈ 1.5 × 10 −8 s at T = 174 K. Eq. (3) with the interpolated experimental value D(174 K) ≈ 8.6 × 10 −9 cm 2 /s then yields L ≈ 2.78 Å.…”