2010
DOI: 10.1007/s00707-009-0239-3
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Hyperelastic materials behavior modeling using consistent strain energy density functions

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Cited by 70 publications
(27 citation statements)
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“…Physically, this criterion describing a process of yielding energy by material when it is deformed towards equilibrium and storing energy when the material is deformed away from equilibrium. Restrictions on the form of the strain energy function that occurs from the Drucker stability criterion are discussed in detail by [17,82,109].…”
Section: Effective Constitutive Model and Optimisation Of Materials Pamentioning
confidence: 99%
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“…Physically, this criterion describing a process of yielding energy by material when it is deformed towards equilibrium and storing energy when the material is deformed away from equilibrium. Restrictions on the form of the strain energy function that occurs from the Drucker stability criterion are discussed in detail by [17,82,109].…”
Section: Effective Constitutive Model and Optimisation Of Materials Pamentioning
confidence: 99%
“…[6][7][8][9][10][11][12][13][14][15][16][17][18][19][20] Brought to you by | New York University Bobst Library Technical Services Authenticated Download Date | 6/23/15 3:08 PM are used to fit the experimental data of the first PiolaKirchhoff stress T against the stretch ratio λ and find the model for the strain energy, which can best represent the mechanical behaviour of the measured samples and obtain the material parameters for that model.…”
Section: Uniaxial Test For Incompressible Hyperelastic Materialsmentioning
confidence: 99%
“…Several strain energy density expressions have been suggested for rubber. Darijani and Naghdabadi used the phenomenological approach due to its relative simplicity and consistency within a continuum framework, to obtain the suitable forms for strain energy density function. They showed that a strain energy function for incompressible materials could be expressed as follows W=w(λ1)+w(λ2)+w(λ3) where w(λi) is the sum of the series as w(λi)=k=1Ak(λimk1)+k=1Bk(λink1) where mk,nk take real positive values and the coefficients Ak and Bk are the material parameters.…”
Section: Fundamentalsmentioning
confidence: 99%
“…In simple tension/compression, we know that σ1=σ,λ1=λ, and σ2=σ3=0. For isotropy of the material, λ2,λ3=λ0.5 and the stress‐deformation relations are combined to give σ=λdWtrue∼dλ, Wtrue∼ =1λσλ dλ where Wtrue∼true(λtrue)=Wtrue(λ,λ0.5,λ0.5true).…”
Section: Fundamentalsmentioning
confidence: 99%
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