2006
DOI: 10.1017/s0013091504000975
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Hyponormal Operators, Weighted Shifts and Weak Forms of Supercyclicity

Abstract: An operator T on a Banach space X is said to be weakly supercyclic (respectively N -supercyclic) if there exists a one-dimensional (respectively N -dimensional) subspace of X whose orbit under T is weakly dense (respectively norm dense) in X. We show that a weakly supercyclic hyponormal operator is necessarily a multiple of a unitary operator, and we give an example of a weakly supercyclic unitary operator. On the other hand, we show that hyponormal operators are never N -supercyclic. Finally, we characterize … Show more

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Cited by 38 publications
(44 citation statements)
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“…He defines: Definition 1.3. An operator T is said to be n-supercyclic, n ≥ 1, if there is a subspace of dimension n in X with dense orbit.These operators have been studied in [1], [3] and [5] and [7]. Feldman gave some different classes of n-supercyclic operators and in particular:…”
mentioning
confidence: 99%
“…He defines: Definition 1.3. An operator T is said to be n-supercyclic, n ≥ 1, if there is a subspace of dimension n in X with dense orbit.These operators have been studied in [1], [3] and [5] and [7]. Feldman gave some different classes of n-supercyclic operators and in particular:…”
mentioning
confidence: 99%
“…Feldman showed that normal operators cannot be N -supercyclic [11]. Later, Bayart and Matheron generalized this result to hyponormal operators [5]. Non-supercyclicity of m-isometric operators on Hilbert spaces has been shown by Faghih-Ahmadi and Hedayatian in [10].…”
Section: Let H Denote An Infinite Dimensional Hilbert Space and B(h) mentioning
confidence: 99%
“…The next example shows that such operators do exist. It is a modification of an example constructed in [2]. By T we denote the unit circle in C: T = {z ∈ C : |z| = 1}.…”
Section: Then T Is Hypercyclic [T M ] Has Dense Range and [T [T Mmentioning
confidence: 99%