In situlaser irradiation: the kinetics of the changes in the nonlinear/linear optical parameters of As₅₀Se₄₀Sb₁₀thin films for photonic applications

Abstract

The photosensitivity of amorphous chalcogenide thin films brings out light-induced changes in the nonlinear and linear optical parameters upon sub-bandgap and bandgap laser irradiation.

Role of tellurium addition on the linear and non‐linear optical, structural, morphological properties of Ag60‐xSe40Tex thin films for nonlinear applications

“…The dielectric constant is generally a complex quantity that consists of both real and imaginary parts: ε = ε r +i ε i. The values of both the parameters are related to the linear refractive index ( n ) and extinction coefficient ( k ) through the relation 62 $$\begin{equation}{\varepsilon _{\rm{r}}} = {\rm{ }}{n^2} - {k^2}\ {\rm{and}}\,\,{\varepsilon _{\rm{i}}} = {\rm{ }}2nk\end{equation}$$…”

“…The dielectric constant is generally a complex quantity that consists of both real and imaginary parts: ε = ε r +iε i. The values of both the parameters are related to the linear refractive index (n) and extinction coefficient (k) through the relation 62 𝜀 r = 𝑛 2 − 𝑘 2 and 𝜀 i = 2𝑛𝑘…”

The impact of fluence dependent proton ion irradiation on the structural and optical properties of Bi5In30Se65 thin films for nonlinear optical devices

“…The OD represents the measure of absorption loss of the incident radiation as it propagates through the materials. The OD can be estimated as, 4 OD = α × d . Fig.…”

Effect of Sb addition on SbxSn1‐xS thin films: The structural, morphological, and linear/nonlinear optical changes for optoelectronic applications

“…have reported the optical properties of Ge 20 Se 70 Sn 10 thin film for optoelectronic applications, the calculated oscillator energy, and the optical bandgap do not follow the rule of E 0 = 2 E g . The obtained values of E 0 and E d were used to calculate the oscillator field strength ( f ), the first‐order moment ( M ‐1 ), and third‐order moments ( M ‐3 ) using the formula, 63 $$\begin{equation}f = {E_0}{E_{\rm{d}}},\quad {M_{ - 1}} = \frac{{{E_{\rm{d}}}}}{{{E_0}}},\quad {M_{ - 3}} = \frac{{{M_{ - 1}}}}{{E_0^2}}\end{equation}$$…”