2019
DOI: 10.1007/978-3-030-17953-3_1
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Identically Self-blocking Clutters

Abstract: A clutter is identically self-blocking if it is equal to its blocker. We prove that every identically selfblocking clutter different from {{a}} is nonideal. Our proofs borrow tools from Gauge Duality and Quadratic Programming. Along the way we provide a new lower bound for the packing number of an arbitrary clutter. 1 The main result All sets considered in this paper are finite. Let V be a set of elements, and let C be a family of subsets of V called members. If no member contains another, then C is said to be… Show more

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Cited by 3 publications
(4 citation statements)
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“…A result that must be noted in the context of Conjecture 9 is the following: For every ideal clutter C where every member and also every cover has cardinality at least two, either χ(C) ≤ 2 or χ(b(C)) ≤ 2 (or both). This result was proved recently, and the proof relied on Gauge Duality in Quadratic Programming [3].…”
Section: Proposition 11mentioning
confidence: 85%
See 1 more Smart Citation
“…A result that must be noted in the context of Conjecture 9 is the following: For every ideal clutter C where every member and also every cover has cardinality at least two, either χ(C) ≤ 2 or χ(b(C)) ≤ 2 (or both). This result was proved recently, and the proof relied on Gauge Duality in Quadratic Programming [3].…”
Section: Proposition 11mentioning
confidence: 85%
“…Similarly, we may assume e / ∈ C i 3 for i ∈ [2]. But now {C 1 j C 2 j : j ∈ [3]} is a 3-cycle cover of M. For (3), suppose E 1 ∩ E 2 = {e, f , g}. Since {e, f , g} is a cocircuit of both M 1 , M 2 , and since cocircuits and circuits of a binary matroid have an even number of elements in common, |C i j ∩ {e, f , g}| ∈ {0, 2} for all i, j.…”
Section: Claim 1 Both F 7 and M(v 8 ) Have 3-cycle Coversmentioning
confidence: 99%
“…that describes yet another mechanism of majority voting, 1 but this decomposition has no essential meaning from the linear algebraic viewpoint, since 1 Let 2 [t] denote the power set (i.e., the family of all subsets) of Et. Recall that maps…”
Section: Introductionmentioning
confidence: 99%
“…In fact, Q 6 is the smallest intersecting clutter which is not ideal ([1], Proposition 1.2). It is worth pointing out that if a clutter and its blocker are both intersecting, then the clutter must be nonideal [3].…”
Section: Introductionmentioning
confidence: 99%