1998
DOI: 10.1002/(sici)1099-0682(199801)1998:1<87::aid-ejic87>3.0.co;2-x
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Imidotitanium Complexes with Heteroallylic Ligands: Synthesis and Solid-State Structure

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Cited by 13 publications
(2 citation statements)
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“…10:1, and whilst these are more compatible with the peaks at 624 cm −1 , the calculations indicate that PdF 5 is the least stable of the palladium fluorides and is unstable with respect to disproportionation to PdF 4 and PdF 6 . Whilst PtF 5 is known, 93,94 there do not appear to be any reputable reports for PdF 5 . 1 It is hard to rationalize why PdF 5 should be formed, but not PdF 3 or even PdF 6 .…”
Section: Discussionmentioning
confidence: 99%
“…10:1, and whilst these are more compatible with the peaks at 624 cm −1 , the calculations indicate that PdF 5 is the least stable of the palladium fluorides and is unstable with respect to disproportionation to PdF 4 and PdF 6 . Whilst PtF 5 is known, 93,94 there do not appear to be any reputable reports for PdF 5 . 1 It is hard to rationalize why PdF 5 should be formed, but not PdF 3 or even PdF 6 .…”
Section: Discussionmentioning
confidence: 99%
“…[ 13,15,16 ] In contrast, the pentafluorides belonging to the RuF 5 structure type (RuF 5 , OsF 5 , RhF 5 , PtF 5 ), which may be described as corrugated tetramers, have fluorine atoms that pack in a distorted hexagonal close packed array. [ 17–20 ] Additionally, within the MoF 5 structure type, the point symmetry of the M 4 F 20 ( M = Nb, Ta, Mo, W) molecule is C 2 h , with a twofold rotation axis running through both M (1) atoms and the perpendicular mirror plane that bisects the M (2), F(1) and F(2) atoms. In the RuF 5 structure type, the M 4 F 20 ( M = Ru, Os, Rh, Pt) molecule has C i point symmetry.…”
Section: Resultsmentioning
confidence: 99%