“…Let the values of a and b be 1 & also let p be 11 for the curve F p Putting this values in equation 1, we get y 2 = x 3 +x +1 (mod 11) The set of solutions are E= {(1,10), (1,1), (3,5), (3,6), (4,2), (4,9), ( Let point P be (6,6), then the doubling operation is. = (3 * 6 2 +1)/ (2 * 6) mod 11 = (108/12) mod 11 = 9…”