“…(5) For current 0, (1,4,11,14) , guess 0, (5,15) and partially encrypt plaintext pairs in (2) , and then select plaintext pairs whose difference (5,15) satisfies the equation (18 (1,4,5,11,14,15) , guess 0, (7,13) and partially encrypt plaintext pairs in (3) , and then select plaintext pairs whose difference (7,13) satisfies (19). We store 2 +103 × 2 −8 = 2 +95 remaining ( (7,13) , SL 1,(7,13) ) and its SN in table (4) indexed by 0,(7,13) .…”