1994
DOI: 10.1016/0040-9383(94)90008-6
|View full text |Cite
|
Sign up to set email alerts
|

Indecomposability of equivalence relations generated by word hyperbolic groups

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1
1
1

Citation Types

3
74
0

Year Published

1994
1994
2013
2013

Publication Types

Select...
6
1

Relationship

0
7

Authors

Journals

citations
Cited by 31 publications
(77 citation statements)
references
References 9 publications
3
74
0
Order By: Relevance
“…It is an intriguing unsolved problem to find a geometric characterization for treeable groups. Theorem 1.3 seems close in spirit to results of Adams (1988Adams ( , 1994; however, it appears that there is no direct implication from one result to the other (S. Adams, R. Lyons and B. Weiss, private communications). The referee has suggested that perhaps the techniques of Adams (1988) could be used to give an alternative proof of our main results.…”
Section: Definitions (I)mentioning
confidence: 78%
“…It is an intriguing unsolved problem to find a geometric characterization for treeable groups. Theorem 1.3 seems close in spirit to results of Adams (1988Adams ( , 1994; however, it appears that there is no direct implication from one result to the other (S. Adams, R. Lyons and B. Weiss, private communications). The referee has suggested that perhaps the techniques of Adams (1988) could be used to give an alternative proof of our main results.…”
Section: Definitions (I)mentioning
confidence: 78%
“…He used this significant property in the process of solving a certain problem concerning equivalence relations generated by hyperbolic groups [2].…”
Section: Chaptermentioning
confidence: 99%
“…Adams [2] investigated invariant Borel maps ϕ : X → M (∂Γ) for a recurrent subrelation S of R, where the word "invariant" means that the map ϕ satisfies…”
Section: Chaptermentioning
confidence: 99%
See 1 more Smart Citation
“…If this action is orbit equivalent to a product action of two discrete groups Γ 1 and Γ 2 on S 1 × S 2 , then either S 1 or S 2 is essentially finite. [2]. Let us illustrate the idea of the proof very roughly in case Γ is the fundamental group of a manifold M of negative curvature.…”
Section: Amenability Superrigidity and Other Applicationsmentioning
confidence: 99%