2019
DOI: 10.1137/18m119642x
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Independent Sets in Hypergraphs and Ramsey Properties of Graphs and the Integers

Abstract: Many important problems in combinatorics and other related areas can be phrased in the language of independent sets in hypergraphs. Recently Balogh, Morris and Samotij [3], and independently Saxton and Thomason [62] developed very general container theorems for independent sets in hypergraphs; both of which have seen numerous applications to a wide range of problems. In this paper we use the container method to give relatively short and elementary proofs of a number of results concerning Ramsey (and Turán prop… Show more

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Cited by 26 publications
(55 citation statements)
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References 60 publications
(130 reference statements)
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“…We will use the following simplification of Theorem 4.7 in [10], a container result, which is itself a consequence of the general container theorems of Balogh, Morris and Samotij [1] and Saxton and Thomason [21]. Note that in [10] the theorem is stated for the homogeneous case Ax = 0 only. However, the result easily generalises to the inhomogeneous case Ax = b.…”
Section: Proof Of Maker's Win In Theoremmentioning
confidence: 99%
See 2 more Smart Citations
“…We will use the following simplification of Theorem 4.7 in [10], a container result, which is itself a consequence of the general container theorems of Balogh, Morris and Samotij [1] and Saxton and Thomason [21]. Note that in [10] the theorem is stated for the homogeneous case Ax = 0 only. However, the result easily generalises to the inhomogeneous case Ax = b.…”
Section: Proof Of Maker's Win In Theoremmentioning
confidence: 99%
“…Let p > Cn −1/m(A) . Note that m(A) > 1 (see Proposition 4.3 in [10]) and thus pn tends to infinity as n tends to infinity. Let R be as in the statement of the theorem and set X :…”
Section: Proof Of Theorem 3(i)mentioning
confidence: 99%
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“…Hence the dimension of these rows must be rk(A) − rk(A Q ) = r Q . We identify a set of r Q linearly independent rows and permute them to the top of the matrix, hence obtaining the promised block decomposition (13). Note that the rank of B is r Q by construction.…”
Section: Ii) If a Is Abundant Then B Is Abundant (Iii) For Any Vectomentioning
confidence: 99%
“…To prove (iii), note that from (13) it follows that for any solution x ∈ S(A, b) = S(P⋅A, P ⋅ b) we S(B, c). The second statement follows by noting that c(P, A, Q, b) = 0 provided that b = 0.…”
Section: Ii) If a Is Abundant Then B Is Abundant (Iii) For Any Vectomentioning
confidence: 99%