2003
DOI: 10.4064/fm177-1-3
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Indestructibility, strongness, and level by level equivalence

Abstract: Abstract. We construct a model in which there is a strong cardinal κ whose strongness is indestructible under κ-strategically closed forcing and in which level by level equivalence between strong compactness and supercompactness holds non-trivially. Introduction and preliminaries.A very surprising fact (see ) is that if there are large enough cardinals in the universe, then indestructibility for either a strong or supercompact cardinal (in the sense of [5] or [13]) is incompatible with level by level equivalen… Show more

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Cited by 4 publications
(3 citation statements)
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“…We 3 Although not directly relevant to this proof, it is actually true that P "Ṗ is ℵ 2 -directed closed". 4 An outline of this argument is as follows. will not provide as many details as in [5], although we will give a reasonably complete proof.…”
Section: We May Use the Usual Diagonalization Argument To Build An M mentioning
confidence: 99%
See 1 more Smart Citation
“…We 3 Although not directly relevant to this proof, it is actually true that P "Ṗ is ℵ 2 -directed closed". 4 An outline of this argument is as follows. will not provide as many details as in [5], although we will give a reasonably complete proof.…”
Section: We May Use the Usual Diagonalization Argument To Build An M mentioning
confidence: 99%
“…For instance, in [8,Theorems 5 and 6], it was shown that if κ < λ are such that κ is either indestructibly supercompact or indestructibly strong and λ is 2 λ supercompact, then B = {δ < κ | δ is δ + strongly compact yet δ is not δ + supercompact} must be unbounded in κ. However, if the universe contains a fairly small number of large cardinals, κ is either strong or supercompact, and κ's supercompactness or strongness exhibits enough indestructibility, then [8,Theorem 8] and [4,Theorem 1] indicate that B may be empty. This sort of occurrence has been further examined in [1,2,3].…”
Section: Introductionmentioning
confidence: 99%
“…To handle when this occurs, we use an idea due to Hamkins, which has also appeared in [5] in a more general context (as well as in this context in [1,Lemma 2.3]). Hamkins' argument is as follows.…”
mentioning
confidence: 99%