“…By Minkowski's inequality, we get from (35), for every q ≥ 1, Using the inequality (11) and noting that | f (e iθ )| = |e isθ f (e iθ )| = |P(ee iθ )|, 0 ≤ θ < 2π, we get from the inequality (36) 2π 0 P(re iθ ) − P(e iθ ) + mβ ε(R n − q) Proof of Theorem 3. We have by Minkowski's inequality, for every q ≥ 1,…”