The proton transfer from one oxygen atom to the other within the intramolecular H-bond in a molecule
like o-hydroxybenzaldehyde (oHBA) would be precluded by a prior rotational isomerism that breaks this H-bond.
The likelihood of such rotamerization in the ground and several excited electronic states is investigated by ab
initio calculations at the CIS and MP2 levels with a 6-31+G** basis set. In the ground state, the energetics
of proton transfer and rotamerization are competitive with one another; both processes are endothermic and
must surmount an energy barrier. Excitation to the singlet or triplet ππ* states presents a situation where
tautomerization to the keto is exothermic, with a small barrier. In contrast, rotamerization is endothermic
with high intervening barriers, so excited-state proton transfer is favored. The opposite situation is encountered
in the nπ* states, where rotations of the hydroxyl and carbonyl groups are facile and lead energetically downhill,
in contrast to the high barriers opposing endothermic tautomerization. The computations provide insights into
the fundamental causes for the discrepancies between the behaviors of the ππ* and nπ* states.