1994
DOI: 10.1515/9783110900095
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Integral Geometry of Tensor Fields

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Cited by 389 publications
(592 citation statements)
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“…If we define the covector field v = (v 1 , v 2 ) on M by 16) then the previous formula can be written as follows:…”
Section: =ẋ(T) = E −µ(X(t)y(t)) Cos θ(T)γ 2 (T) =ẏ(T) = E −µ(X(t)ymentioning
confidence: 99%
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“…If we define the covector field v = (v 1 , v 2 ) on M by 16) then the previous formula can be written as follows:…”
Section: =ẋ(T) = E −µ(X(t)y(t)) Cos θ(T)γ 2 (T) =ẏ(T) = E −µ(X(t)ymentioning
confidence: 99%
“…In [21], the linear problem is considered under some assumption that is weaker than the simplicity. There is also a couple of results for manifolds with nonconvex boundary [16,6]. In the case of a simple manifold, it is known that the solenoidal part of any tensor field f ∈ Z 2 (S m τ M ) is smooth [4,17,20] and the kernel Z ∞ (S m τ M ) of the ray transform has a finite dimension modulo potential fields [15].…”
Section: Introductionmentioning
confidence: 99%
“…(42b) and (42d) we learn that elements of the kernel of the ray transform can be characterized by the identical vanishing of a differential expression of the vector/tensor components w i , u ij . The differential operator acting in (42b) and (42d) is generically called the Saint-Venant operator [13]. Its vanishing can be understood as an integrability condition ensuring the existence of the scalar/vector fields φ and v occuring in eqs.…”
Section: Case Bmentioning
confidence: 99%
“…Finally, we might wonder whether there is any more information to be retrieved from the ray transforms Iw and Iu, or alternatively Ï and Í, as so far we could only reconstruct one tensor component from these data. The answer is no: As proven in [13], if any two stress tensors σ (1) and σ (2) satisfy (26, 27) and σ (1) 33 = σ (2) 33 then they produce the same ray transforms, Iw (1) = Iw (2) and Iu (1) = Iu (2) . As a consequence, the retrieval of one tensor component is the maximum information to be gleaned from a ray transform which is performed for horizontal lines only.…”
Section: Longitudinal and Transverse Tensor Componentsmentioning
confidence: 99%
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