“…Then the A4-graph is connected with diameter 3. The computational calculations inside GAP [8] led to the following results: 0 (t)={t}, 1 (t)={ (3,4,6), (1,4,6), (2,4,6), (3,5,4), (1,5,4), (2,5,4), (3,6,5), (1,6,5),(2,6,5)}, 2 (t)={ (3,4,5), (1,4,5), (2,4,5), (3,5,6), (1,5,6), (2,5,6), (3,6,4), (1,6,4), (2,6,4),…”