“…If π’ β πΌ π,4 and π£ β 0, 31+58π+28π 2 βπ’ (30+58π+28π 2 ) 182π + 84π 2 β π’ 100 + 182π + 84π 2 β π£ 36 + 56π + 21π 2 36 + 56π + 21π 2 e 1 + + 17 + 32π + 14π 2 β π’ 20 + 34π + 14π 2 36 + 56π + 21π 2 π΅ π,4 + π’ 48 + 98π + 49π 2 β 39 β 91π β 49π 2 36 + 56π + 21π 2 π΅ π+1,1and π (π’, π£) = 0. The same holds when π’ β πΌ π,4 and π£ β 0, 44+70π+28π 2 βπ’ (43+70π+28π 2 )If π’ β πΌ π,4 and π£ β 31+58π+28π 2 βπ’ (30+58π+28π 2 ) 182π + 84π 2 β π’(100 + 182π + 84π 2 ) β π£(36 + 56π + 21π 2 ) 36 + 56π + 21π 2 e 1 + + (1 + π)(11 + 7π) 103 + 182π + 84π 2 β π’(100 + 182π + 84π 2 ) β π£(36 + 56π + 21π 2 )Similarly, we getπ π,1 = (1 + 7π + 7π 2 ) π΄ π,128(1 + π)(1 + 3π)4 (2 + 7π)4 (3 + 7π)4 (4 + 7π)4 ,whereπ΄ π,1 = 480574 + 12906866π + 157271760π 2 + 1149521334π 3 + 5612285145π 4 + + 19278934535π 5 + 47770884833π 6 + 86016481159π 7 + 111679016743π 8 + + 101939513907π 9 + 62077730148π 10 + 22635902898π 11 + 3735591048π 12 . 14π + 7π 2 ) π΄ π,2 224(1 + π)(1 + 2π) 3 (2 + 7π) 4 (3 + 7π) 4 (4 + 7π) 4 ,andπ π,2 = 11780 + 111142π + 430951π 2 + 875637π 3 + 978656π 4 + 566832π 5 + 131712π 6 224(1 + 2π) 3 (3 + 7π) 4 (6 + 14π + 7π 2 ) ,whereπ΄π,2 = 1561176 + 35176776π + 356105548π 2 + 2137950448π 3 + + 8458603286π 4 + 23158717414π 5 + 44778314889π 6 + 61151030584π 7 + + 57807289939π 8 + 36026947376π 9 + 13321631568π 10 + 2213683584π 11 .…”