“…For t ≡ 0, 1 (mod 4) (respectively t ≡ 2, 3 (mod 4)), we can obtain a (3 tn )-decomposition of S t n by using a Langford sequence (respectively hooked Langford sequence) of order t and defect 5, which exists since t ≥ 9, to partition S t into difference triples (see [90,91]). So we have a (3 tn )-decomposition of S t n , and require a (4 qn , n h )-decomposition of K n − {1, 2, 3, 4, 6}∪S t n .…”