2017
DOI: 10.1016/j.endm.2017.07.026
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Lattice walks in the octant with infinite associated groups

Abstract: Continuing earlier investigations of restricted lattice walks in N 3 , we take a closer look at the models with infinite associated groups. We find that up to isomorphism, only 12 different infinite groups appear, and we establish a connection between the group of a model and the model being Hadamard.

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Cited by 2 publications
(10 citation statements)
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“…To summarize, classifying the triangles is close to, but different from classifying the groups. The latter task has already been achieved in [2] (finite group case; we have reproduced their results in Table 4) and [49] (infinite groups; see our Table 1), using a heavy computer machinery. However, the group classification is more precise, in the sense that the spherical triangle does not determine everything: infinite group models can have a tiling triangle, and Hadamard models are not the only ones to have birectangular triangles.…”
mentioning
confidence: 54%
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“…To summarize, classifying the triangles is close to, but different from classifying the groups. The latter task has already been achieved in [2] (finite group case; we have reproduced their results in Table 4) and [49] (infinite groups; see our Table 1), using a heavy computer machinery. However, the group classification is more precise, in the sense that the spherical triangle does not determine everything: infinite group models can have a tiling triangle, and Hadamard models are not the only ones to have birectangular triangles.…”
mentioning
confidence: 54%
“…A model labeled "both" is simultaneously (1, 2)-type and (2, 1)-type Hadamard. The total number of models is computed in [13], the number of (in)finite groups in [13,32,49] and the refined statistics on 3D Hadamard models in [48] For each type, an example is presented in Figure 4: for the (2, 1)-type we have taken U (x, y) = x + x + y + y (the 2D simple walk, see Figure 7), V (x, y) = x + xy + xy + xy + y (a scarecrow model, see again Figure 7) and T (z) = z + z. For the (1, 2)-type we have χ(x, y, z) = U (z) + V (z)T (x, y) (permutation of the variables in the definition (9)), with U (z) = z + z, V (z) = z + 1 + z and T (x, y) the generating function of the same scarecrow model as above.…”
Section: 2mentioning
confidence: 99%
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