2018
DOI: 10.1142/s0129167x18500805
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Linear stability and stability of syzygy bundles

Abstract: Let C be a smooth irreducible projective curve and let (L, H 0 (C, L)) be a complete and generated linear series on C. Denote by ML the kernel of the evaluation map H 0 (C, L) ⊗ OC → L. The exact sequence 0 → ML → H 0 (C, L) ⊗ OC → L → 0 fits into a commutative diagram that we call the Butler's diagram. This diagram induces in a natural way a multiplication map on global sections mW :is a subspace and S ∨ is the dual of a subbundle S ⊂ ML. When the subbundle S is a stable bundle, we show that the map mW is sur… Show more

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Cited by 6 publications
(8 citation statements)
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“…The first and third named author proved in [CTL18] that Conjecture 2.6 does hold in the two opposite cases: when C is a hyperelliptic curve and when C is a Brill-Noether-Petri general curve.…”
Section: Notations and Previous Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…The first and third named author proved in [CTL18] that Conjecture 2.6 does hold in the two opposite cases: when C is a hyperelliptic curve and when C is a Brill-Noether-Petri general curve.…”
Section: Notations and Previous Resultsmentioning
confidence: 99%
“…In fact the first and third named authors showed in [CTL18] that the conjecture holds when C is a hyperelliptic curve or a Brill-Noether-Petri general curve.…”
Section: Introductionmentioning
confidence: 99%
“…In [MS12], this was shown to be true in many cases and some counterexamples were given. When V = H 0 (E), the question has been answered in the affirmative for Petri curves and hyperelliptic curves [CT18], but counter-examples are known for smooth plane curves of genus 7 [CMT20].…”
Section: Butler's Conjecturementioning
confidence: 99%
“…Let L ∈ P ic d (C) be a globally generated line bundle over a general curve C of genus g with h 0 (L) = r+1. In ( [3], Corollary 4.3), the authors proved that the syzygy bundle M L is semistable (not stable) if and only if all the following three conditions hold:…”
Section: Syzygy Bundles and Theta Divisorsmentioning
confidence: 99%
“…Proof. We recall by ( [3], Corollary 4.3) that if M L is strictly semistable, then h 1 (L) = 0, r divides g and there exists an effective divisor Z of degree 1 + g r such that h 0 (L(−Z)) = r and L(−Z) is generated. The vector bundles M L and M L(−Z) fit in the following exact sequence…”
Section: Syzygy Bundles and Theta Divisorsmentioning
confidence: 99%