2017
DOI: 10.1007/s00605-017-1024-3
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Logarithmic coefficients and a coefficient conjecture for univalent functions

Abstract: Abstract. Let U(λ) denote the family of analytic functions f (z), f (0) = 0 = f (0) − 1, in the unit disk D, which satisfy the condition z/f (z) 2 f (z) − 1 < λ for some 0 < λ ≤ 1. The logarithmic coefficients γ n of f are defined by the formula log(f (z)/z) = 2 ∞ n=1 γ n z n . In a recent paper, the present authors proposed a conjecture that if f ∈ U(λ) for some 0 < λ ≤ 1, then |a n | ≤ n−1 k=0 λ k for n ≥ 2 and provided a new proof for the case n = 2. One of the aims of this article is to present a proof of … Show more

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Cited by 53 publications
(52 citation statements)
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“…In [15], the authors considered the logarithmic coefficients of the functions f in the class G(c) for some c ∈ (0, 1] and they got the estimate |γ n | ≤ c 2(c + 1)n , n ∈ N.…”
Section: Resultsmentioning
confidence: 99%
“…In [15], the authors considered the logarithmic coefficients of the functions f in the class G(c) for some c ∈ (0, 1] and they got the estimate |γ n | ≤ c 2(c + 1)n , n ∈ N.…”
Section: Resultsmentioning
confidence: 99%
“…Let µ(n) be the Möbius function of the positive integer n, that is, (a) µ(1) = 1, (b) µ(n) = 0, if a square number is a divisor of n, (c) µ(n) = (−1) r , if n is the product of r pairwise disjoint prime numbers. During their efforts to prove a coefficient conjecture (see [4,Conjecture 1]) for some classes of univalent functions, the second and the third authors of the present paper considered an inequality that concerned the Mertens function. See also [5].…”
Section: Introduction and Main Resultsmentioning
confidence: 99%
“…We know that proving inequalities concerning |γ n |'s is considered to be a challenging problem till date (see f.i. [17,22] and references therein) due to the unavailability of the sharp bounds on |γ n |'s for n ≥ 3, where f ∈ S. Inspired by this fact, in this article we have considered the problem of establishing Bohr inequalities similar to the inequality (1.1) for log(f (z)/z). More precisely, we will say that log(f (z)/z) has Bohr radius r 0 ∈ (0, 1] if…”
Section: Introductionmentioning
confidence: 99%