2019
DOI: 10.1103/physreva.99.052501
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Lower bound on the Hartree-Fock energy of the electron gas

Abstract: The Hartree-Fock ground state of the Homogeneous Electron Gas is never translation invariant, even at high densities. As proved by Overhauser, the (paramagnetic) free Fermi Gas is always unstable under the formation of spin or charge density waves. We give here the first explicit bound on the energy gain due to the breaking of translational symmetry. Our bound is exponentially small at high density, which justifies a posteriori the use of the non-interacting Fermi Gas as a reference state in the large-density … Show more

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Cited by 30 publications
(37 citation statements)
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“…We need an estimate on this eigenvalue. This is what has been accomplished in [HS10] for regular potentials and in [GHL19] in the critical case d = 2, 3 and s = 1. Following the exact same method, we can prove the Lemma 26 (Estimate on the first eigenvalue of |∆ + 1| − ε|x| −s ).…”
Section: 52supporting
confidence: 76%
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“…We need an estimate on this eigenvalue. This is what has been accomplished in [HS10] for regular potentials and in [GHL19] in the critical case d = 2, 3 and s = 1. Following the exact same method, we can prove the Lemma 26 (Estimate on the first eigenvalue of |∆ + 1| − ε|x| −s ).…”
Section: 52supporting
confidence: 76%
“…Proof of Lemma 26. The cases d = 2, 3 and s = 1 have been handled in [GHL19]. The proof is exactly the same in higher dimensions.…”
Section: 52mentioning
confidence: 92%
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“…Some authors define the correlation energy with respect to the minimum of the Hartree–Fock functional instead. For the present translation invariant setting, it was recently proved [ 31 ] that the energy of the plane wave state and the minimal Hartree–Fock energy differ only by an exponentially small amount as . However, for systems that are not translation invariant, the ground state of non-interacting fermions will not even be a stationary point of the interacting Hartree–Fock functional.…”
mentioning
confidence: 99%