2021
DOI: 10.1007/s40819-021-01206-z
|View full text |Cite
|
Sign up to set email alerts
|

Lucas Wavelet Scheme for Fractional Bagley–Torvik Equations: Gauss–Jacobi Approach

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1
1
1

Citation Types

0
1
0

Year Published

2022
2022
2024
2024

Publication Types

Select...
6

Relationship

0
6

Authors

Journals

citations
Cited by 9 publications
(8 citation statements)
references
References 45 publications
0
1
0
Order By: Relevance
“…Moreover, in the Examples 5.4) and 5.5 two-term linear and nonlinear fractional order differential equations are considered and the approximate results are obtained with the precision surpassing 10 −77 and with almost zero error, respectively. Further, the numerical results obtained in Example 5.6 are more accurate as compare to the existing results for the Caputo fractional derivative [35,42,43]. The salient feature of the suggested technique lies in its straightforward implementation,…”
Section: Discussionmentioning
confidence: 70%
See 3 more Smart Citations
“…Moreover, in the Examples 5.4) and 5.5 two-term linear and nonlinear fractional order differential equations are considered and the approximate results are obtained with the precision surpassing 10 −77 and with almost zero error, respectively. Further, the numerical results obtained in Example 5.6 are more accurate as compare to the existing results for the Caputo fractional derivative [35,42,43]. The salient feature of the suggested technique lies in its straightforward implementation,…”
Section: Discussionmentioning
confidence: 70%
“…Example 5.6. Let us consider the initial value Bagley-Trovik equation [35,42,43] derived by AB-fractional derivative…”
Section: Numerical Examplesmentioning
confidence: 99%
See 2 more Smart Citations
“…Example Consider the following FFDE: left leftarrayarrayarrayDα,ν,βy(t)+y(t)=0,arrayy(0)=1,y(0)=0.$$ {\displaystyle \begin{array}{ll}& {D}^{\alpha, \nu, \beta}\kern0.3em y(t)+y(t)=0,\\ {}& \kern1.20em y(0)=1,\kern0.3em {y}^{\prime }(0)=0.\end{array}} $$ The exact solution when α=2$$ \alpha =2 $$ is yfalse(tfalse)=expfalse(itfalse)+expfalse(prefix−itfalse)2$$ y(t)=\frac{\exp (it)+\exp \left(- it\right)}{2} $$ 64 …”
Section: Numerical Simulation Of Fractal‐fractional Problemsmentioning
confidence: 99%