1967
DOI: 10.1007/bf02771612
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Measurable cardinals and the continuum hypothesis

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Cited by 324 publications
(270 citation statements)
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“…By the results of [14], there must exist some normal measure µ β ∈ V R β and some term B β such that Pα "B β ∈ µ β and B β ⊆ A β ". By replacing each A β with…”
Section: Theorem 8 the Following Theories Are Equiconsistent: A) Zfc mentioning
confidence: 99%
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“…By the results of [14], there must exist some normal measure µ β ∈ V R β and some term B β such that Pα "B β ∈ µ β and B β ⊆ A β ". By replacing each A β with…”
Section: Theorem 8 the Following Theories Are Equiconsistent: A) Zfc mentioning
confidence: 99%
“…Proof: Since |P| = κ and V "No cardinal η > κ is measurable", by the results of [14], V P "No cardinal η > κ is measurable" as well. We may thus assume that δ < κ and V P "δ is measurable", since V P "κ is supercompact and a limit of members of C".…”
Section: Lemma 24 V P "Any Measurable Cardinal Is Either a Member Ofmentioning
confidence: 99%
“…Again by the results of [20], V "δ is λ strongly compact" as well. Thus, by level by level equivalence between strong compactness and supercompactness in V , V "Either δ is λ supercompact, or δ is a measurable limit of cardinals γ which are λ supercompact".…”
Section: The Proof Of Theoremmentioning
confidence: 69%
“…We must therefore have that λ < δ , for if not, then it must be true that in both V P ρ and V P ρ * Q = V P , δ is strongly compact up to δ . Since P ρ is forcing equivalent to a partial ordering having size less than δ, by the Lévy-Solovay results [20], V "δ < κ is strongly compact up to δ ". Hence, again by [3, Lemma 1.1], V "δ is strongly compact", a contradiction to the fact that by level by level equivalence between strong compactness and supercompactness in V , V "κ is both the least strongly compact and least supercompact cardinal".…”
Section: The Proof Of Theoremmentioning
confidence: 88%
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