2017
DOI: 10.1112/blms.12069
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Measurable Steinhaus sets do not exist for finite sets or the integers in the plane

Abstract: Abstract. A Steinhaus set S ⊆ Rd for a set A ⊆ R d is a set such that S has exactly one point in common with τA, for every rigid motion τ of R d . We show here that if A is a finite set of at least two points then there is no such set S which is Lebesgue measurable.An old result of Komjáth says that there exists a Steinhaus set for A = Z × {0} in R 2 . We also show here that such a set cannot be Lebesgue measurable.

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Cited by 5 publications
(3 citation statements)
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“…It is known that every set of cardinality 3, 4, 5 or 7 is a Jackson set (see [3]). It is also known that for every finite set K ⊂ R k having at least two elements there is no measurable sets that intersect each congruent copy of K in exactly one point [9]. Now, we show that if a set of cardinality at least two has the Pompeiu property, then it is a Jackson set.…”
Section: Introductionmentioning
confidence: 73%
“…It is known that every set of cardinality 3, 4, 5 or 7 is a Jackson set (see [3]). It is also known that for every finite set K ⊂ R k having at least two elements there is no measurable sets that intersect each congruent copy of K in exactly one point [9]. Now, we show that if a set of cardinality at least two has the Pompeiu property, then it is a Jackson set.…”
Section: Introductionmentioning
confidence: 73%
“…Kolountzakis [17,16] and Kolountzakis and Wolff [22] proved that any measurable set in the plane that has the measurable Steinhaus property must necessarily have very slow decay at infinity (any such set must have measure 1). In [22] it was also shown that there can be no measurable Steinhaus sets in dimension d ≥ 3 (tiling with all rotates ρZ d , where ρ is in the full orthogonal group) a fact that was also shown later by Kolountzakis and Papadimitrakis [20] by a very different method. See also [5,25,6,29].…”
Section: Smentioning
confidence: 79%
“…Kolountzakis [14,13] and Kolountzakis and Wolff [19] proved that any measurable set in the plane that has the measurable Steinhaus property must necessarily have very slow decay at infinity (any such set must have measure 1). In [19] it was also shown that there can be no measurable Steinhaus sets in dimension d ≥ 3 (tiling with all rotates ρZ d , where ρ is in the full orthogonal group) a fact that was also shown later by Kolountzakis and Papadimitrakis [17] by a very different method. See also [3,24,4,27].…”
mentioning
confidence: 79%